Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi ≤ 400), a 'desirability' factor Di (1 ≤ Di ≤ 100), and can be used at most once. Bessie can only support a charm bracelet whose weight is no more than M (1 ≤ M ≤ 12,880).
Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the maximum possible sum of ratings.
Input
* Line 1: Two space-separated integers: N and M
* Lines 2..N+1: Line i+1 describes charm i with two space-separated integers: Wi and DiOutput
* Line 1: A single integer that is the greatest sum of charm desirabilities that can be achieved given the weight constraints
Sample Input
4 6 1 4 2 6 3 12 2 7
Sample Output
23
#include <iostream> #include <cstdio> #include <cstring> using namespace std; int main() { int N,M,W[3500],D[3500],dp[3500]; while(cin>>N>>M) { for(int i=0;i<N;i++){ scanf("%d%d",&W[i],&D[i]); } memset(dp,0,sizeof(dp)); for(int i=0;i<N;i++) { for(int j=M;j>=W[i];j--) { dp[j]=max(dp[j-W[i]]+D[i],dp[j]); } } cout<<dp[M]<<endl; } return 0; }
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